Let's say you have a normal chess board, like in the picture to the right. It is obvious that you can use domino tiles to fully cover the whole board, where each tile covers two squares of the chess board.
But what if I take down two squares - a8 and h1 (top-left and bottom-right)? Can the board still be fully covered with domino tiles (that do not co-exist on any square)? If so - give me your solution. If not - prove that it can't be done.
4 comments:
Anonymous
said...
it cannot - you will not have a matching number of black & white squares
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4 comments:
it cannot - you will not have a matching number of black & white squares
Correct. Thanks for your participation!
Oh...I was about to count the spots and then I happened to read to comment so I figured that makes sense and stopped :)
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